File opened without the
with statement PTC-W0010
Anti-pattern
Critical
2 years ago
—
2 years old
Use the
with statement to open a file20 return math.ceil((area/(0.5*trianglebase)))
21
22if __name__ == '__main__':
23 fptr = open(os.environ['OUTPUT_PATH'], 'w')24
25 first_multiple_input = input().rstrip().split()
26Use the
with statement to open a file17 # Write your code here
18 return n+1
19if __name__ == '__main__':
20 fptr = open(os.environ['OUTPUT_PATH'], 'w')21
22 t = int(input().strip())
23Use the
with statement to open a file17 # Write your code here
18 return n+1
19if __name__ == '__main__':
20 fptr = open(os.environ['OUTPUT_PATH'], 'w')21
22 t = int(input().strip())
23Use the
with statement to open a file17 # Write your code here
18 return n+1
19if __name__ == '__main__':
20 fptr = open(os.environ['OUTPUT_PATH'], 'w')21
22 t = int(input().strip())
23Use the
with statement to open a file17 # Write your code here
18 return n+1
19if __name__ == '__main__':
20 fptr = open(os.environ['OUTPUT_PATH'], 'w')21
22 t = int(input().strip())
23
Description
Opening a file using with statement is preferred as function open implements the context manager protocol that releases the resource when it is outside of the with block. Not doing so requires you to manually release the resource.
Bad practice
f = open('/tmp/.deepsource.toml', 'w')
f.write("config file.")
# No `f.close()` statement: file may remain unaccessible
Preferred:
with open('/tmp/.deepsource.toml', 'w') as f:
f.write("config file.")