107 return
108
109 urlscheme = re.search(
110 "sileo:\/\/package\/([a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+(\.[a-zA-Z0-9]+)+)", message.content)111 if urlscheme is None:
112 return
113
107 return
108
109 urlscheme = re.search(
110 "sileo:\/\/package\/([a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+(\.[a-zA-Z0-9]+)+)", message.content)111 if urlscheme is None:
112 return
113
107 return
108
109 urlscheme = re.search(
110 "sileo:\/\/package\/([a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+(\.[a-zA-Z0-9]+)+)", message.content)111 if urlscheme is None:
112 return
113
107 return
108
109 urlscheme = re.search(
110 "sileo:\/\/package\/([a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+(\.[a-zA-Z0-9]+)+)", message.content)111 if urlscheme is None:
112 return
113
107 return
108
109 urlscheme = re.search(
110 "sileo:\/\/package\/([a-zA-Z0-9]+(\.[a-zA-Z0-9]+)+(\.[a-zA-Z0-9]+)+)", message.content)111 if urlscheme is None:
112 return
113
Backslash is present in the literal string but is not a valid escape sequence. If it is intended to be an escape sequence, use the correct escape characters. If it is intended to be a literal backslash, it can either be replaced with with an escaped backslash \\
, or you can add an r
prefix to make it a "raw" string.
filepath = "C:\myfiles\run.py"
filepath = "C:\\myfiles\\run.py" # use `\\` to render one backslash
filepath = r"C:\myfiles\run.py" # use the `r` prefix to avoid unnecessary escapes